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Since : \[A=\{4,5,6\}\] then : \[P(A)=P(4)+P(5)+P(6)=\frac1{20}+\frac{1}{20}+\frac{3}{20}=\frac5{20}=\frac14\] And since : \[B=\{6,7\}\] then : \[P(B)=P(6)+P(7)=\frac3{20}+\frac3{20}=\frac{6}{20}=\frac{3}{10}\]
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