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We have : \[\sqrt[y]{x^y}=\left(x^y\right)^{\frac1y}=x=25\\ x^{3/2}=\sqrt{x^3}=x\sqrt{x}=25\times\sqrt{25}=25\times5=125 \\\sqrt{x}=\sqrt{25}=5 \] Hence : \[\frac{\sqrt[y]{x^y}x^{3/2}}{\sqrt x}=\frac{25\times125}{5}=625\]
\[x=25\ , \ y=-2\]\[\huge \frac{\sqrt[y]{x^y}x^{3/2}}{\sqrt{x}}\] \[\huge \frac{(x^y)^{1/y}\cdot x^{3/2}}{x^{1/2}}= \frac{x\cdot x^{3/2}}{x^{1/2}}\]\[\large \frac{x^{5/2}}{x^{1/2}}= x^2 = (25)^2 = 625\]
thanks both of you :D
np, lol.
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