Question

solve this :

Answer 1

We have :
\[\sqrt[y]{x^y}=\left(x^y\right)^{\frac1y}=x=25\\
x^{3/2}=\sqrt{x^3}=x\sqrt{x}=25\times\sqrt{25}=25\times5=125
\\\sqrt{x}=\sqrt{25}=5
\]
Hence :
\[\frac{\sqrt[y]{x^y}x^{3/2}}{\sqrt x}=\frac{25\times125}{5}=625\]

Answer 2

\[x=25\ , \ y=-2\]\[\huge \frac{\sqrt[y]{x^y}x^{3/2}}{\sqrt{x}}\]
\[\huge \frac{(x^y)^{1/y}\cdot x^{3/2}}{x^{1/2}}= \frac{x\cdot x^{3/2}}{x^{1/2}}\]\[\large \frac{x^{5/2}}{x^{1/2}}= x^2 = (25)^2 = 625\]

Answer 3

thanks both of you :D

Answer 4

np, lol.