Question

solve this :

Answer 1

http://www.lightshot.skillbrains.com For your screenshots :)

Answer 2

\[\frac{(x-y)(x^4-y^4)}{x^3+xy^2+x^2y+y^3}\]Factorize the numerator and denominator.\[=\frac{(x-y)^2(x+y)(x^2+y^2)}{x^2(x+y)+y^2(x+y)}\]\[=\frac{(x-y)^2(x+y)(x^2+y^2)}{(x^2+y^2)(x+y)}\]I think you know the rest.

Answer 3

@Callisto how did you factorize the numerator? :o

Answer 4

Oh wait....a minute...it'd be..

Answer 5

(x-y)(x^2-y^2)(x^2+y^2) right? haha.

Answer 6

We have :
\[(x^4-y^4)=(x^2-y^2)(x^2+y^2)=(x-y)(x+y)(x^2+y^2)=4(x^3+xy^2+yx^2+y^3)\]
hence :
\[\frac{(x-y)(x^4-y^4)}{x^3+xy^2+yx^2+y^3}=\frac{(x-y)\times\left(4(x^3+xy^2+yx^2+y^3)\right)}{x^3+xy^2+yx^2+y^3}=4^2=16\]

Answer 7

And\[(x-y)(x^2-y^2)(x^2+y^2)\]\[=(x-y)(x+y)(x-y)(x^2+y^2)\]\[=(x-y)^2(x+y)(x^2+y^2)\]

Answer 8

Gotcha. This happens when you're up at 3 am doing math xD

Answer 9

@Jhannybean i cannot open that link :(
@Callisto and @Noura11 thanks both of you :)