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Mathematics 10 Online
OpenStudy (anonymous):

PLEASE HELP DDD: (vertex) x=-b/2a Use the graphing technology of your choice to graph the above equation and find the vertex value. Set rounding to 5 places. Save a copy of this graph and paste or attach it to this Worksheet.

OpenStudy (anonymous):

I also have to figure out How long the water from your fountain will remain in the air. The fountain I chose is King Fahd fountain.

OpenStudy (anonymous):

The coordinates are x=1, y=-4

OpenStudy (anonymous):

would help to have the equation

OpenStudy (anonymous):

Oh, sorry. y = -16x2 + 341.7 + 0

OpenStudy (anonymous):

a =-16 b =341.73 c =0

OpenStudy (anonymous):

ok so it looks like you are in good shape

OpenStudy (anonymous):

Well that's good XD

OpenStudy (anonymous):

\[\large \frac{-b}{2a}=\frac{341.7}{32}\]

OpenStudy (anonymous):

Is this for the height of the fountain or for the graph?

OpenStudy (anonymous):

where did the 341.7 come from?

OpenStudy (anonymous):

If speed is given in miles per hour, follow the 2 step conversion process, showing your work below, to arrive at the number of feet per second. Step 1: Multiply the miles per hour given by the number of feet in a mile. Step 2: Divide the above feet per hour by the number of seconds in an hour. Indicate the feet per second (velocity) of your fountain. Feet per second (v) ≈ 341.7

OpenStudy (anonymous):

is that the velocity of the water?

OpenStudy (anonymous):

Yeah.

OpenStudy (anonymous):

ok so then the maximum height will presumably occur when \(t=\frac{341.7}{32}=10.678125\)

OpenStudy (anonymous):

I have 261 meters for the maximum height

OpenStudy (anonymous):

You're probably right with what you have though

OpenStudy (anonymous):

the height is given by \(h(t)=-16t^2+341.7t \) and so to find the max you need to compute \[h(10.678125)=-16(10.67815)^2+3412.7\times 10.67815\]

OpenStudy (anonymous):

ohh alright.

OpenStudy (anonymous):

i had a typo there

OpenStudy (anonymous):

Oh haha XD whoopsy

OpenStudy (anonymous):

\[h(10.678125)=-16(10.67815)^2+341.7\times 10.67815\]

OpenStudy (anonymous):

Okay!

OpenStudy (anonymous):

So should I try to solve?

OpenStudy (anonymous):

i get 1824 feet which is too large according to wiki it is 1024 feet

OpenStudy (anonymous):

Yeah I got that from Wiki :P

OpenStudy (anonymous):

but you did do the conversion correctly, i just checked it

OpenStudy (anonymous):

4000 cubic meters of water remain in the air aparently, but I don't think that helps us any.

OpenStudy (anonymous):

Yay!

OpenStudy (anonymous):

no water will have other forces acting on it, it is not like a ball being thrown up at that speed

OpenStudy (anonymous):

also it says "can reach a speed of" so i wouldn't fret too much

OpenStudy (anonymous):

Alright!

OpenStudy (anonymous):

here is a nice picture, looks like the water stays in the air a little more than 22 seconds you can solve exactly in two steps http://www.wolframalpha.com/input/?i=-16%28x%29^2%2B341.7*x+domain+0+..+22

OpenStudy (anonymous):

i mean a little more than 21 seconds

OpenStudy (anonymous):

king fahad??!!

OpenStudy (anonymous):

Yeah!

OpenStudy (anonymous):

Hello?

OpenStudy (anonymous):

yeah?

OpenStudy (anonymous):

So is that the graph I need?

OpenStudy (anonymous):

yes, that is a good graph i think

OpenStudy (anonymous):

Yay! Thank you so much :D

OpenStudy (anonymous):

yw

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