Question

If I have 45.1 moles of magnesium and 39.8 moles of HCl, how many moles of MgCl2 are formed?

Answer 1

The balanced equation
Mg + 2HCl ----> MgCl2 + H2
@phi

Answer 2

so first I need to find the molar mass correct?

Answer 3

the molar mass of Mg, H, and CI

Answer 4

find first which is limiting agent

Answer 5

H

Answer 6

LOL H mean :)

Answer 7

huh?

Answer 8

for one mole of Mg u need 2 mole of HCl right then
can you tell 45.1 moles of mg needs how many moles of HCl

Answer 9

90.2 moles of HCI

Answer 10

but how many moles are mentioned in problem

Answer 11

39.8

Answer 12

39.8 moles HCI

Answer 13

ooooo wait so I need to divide that by 2

Answer 14

and that's how many moles HCI I can use

Answer 15

noo need
it mean that HCl is a limiting reagent and Mg is present in excess got it
i showed you how to find limiting agent

Answer 16

HCI is limiting reagent

Answer 17

so I dived mile/theoretical moles, huh I'm confused

Answer 18

wait let me say something LOL:)

Answer 19

all I have written down is 1 mole mg=2 mole HCI
45.1 moles mg=

Answer 20

ok lol srry

Answer 21

since mg in excess in ur calculation you should not consider it

Answer 22

2 moles of HCl give rise to 1 mole of mg cl2
then 39.8moles of HCl give rise to =

Answer 23

limiting agent mean the yield of product depends on it and not on the other reactant

Answer 24

can u caluclate now

Answer 25

what do you mean give rise
??????????????
allow??????

Answer 26

2 moles of HCl produces 1 mole of mg cl2
then 39.8moles of HCl produces =

Answer 27

19.9 moles mg cl2

Answer 28

yup:)

Answer 29

oh well that made sense :)

Answer 30

So if I have 45.1 moles of magnesium and 39.8 moles of HCl, 19.9 moles of MgCl2 are formed

Answer 31

right?

Answer 32

yes :)

Answer 33

ty!!!!!!!!!!!!!!!!!!!!!

Answer 34

i think im gettin the hang of this

Answer 35

:)

Answer 36

hang of this mean

Answer 37

What if I have 2.5 moles of magnesium and 2.5 moles of HCL, how many moles of hydrogen are formed?

Answer 38

how would I figure out that one?

Answer 39

same way?

Answer 40

@chmvijay

Answer 41

yaaa same thing find out which is limiting agent again and proceed