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OpenStudy (anonymous):
In the reaction Mg (s) + 2HCl (aq) H2 (g) + MgCl2 (aq), how many moles of hydrogen gas will be produced from 75.0 milliliters of a 1.0 M HCl in an excess of Mg?
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OpenStudy (blueraverwolf):
moles HCl = 0.0750 L x 1.0 M = 0.0750 the ratio between HCl and H2 is 2 : 1 moles H2 = 0.0750/2 = 0.0375
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