What if I have 2.5 moles of magnesium and 2.5 moles of HCL, how many moles of hydrogen are formed? My balanced equation is Mg + 2HCl ----> MgCl2 + H2
@chmvijay
Ok so my limiting agent is Mg?
1 mole of mg requires = 2 mole of HCl 2.5 moles of mg requires = 5 moles of HCl but you have only 2.5 moles of HCl now u say the limiting agent
the limiting agent is HCI?
mean if 2.5 moles of Mg want to react completely it needs atleast 5 moles of HCl but in ur question they have given only 2.5 moles of HCl are there now which is limiting agent
HCI because it limits you because you only have half of what you need correct?
right?
@chmvijay
yaaa correct :)
now proceed further
hello say something
sorry lost internet for a sec
so HCI is the limiting reactant which makes Mg the excess reactant
@chmvijay
@phi help a girl out?
@yrelhan4
anybody?
ok so I have the balanced equation, and I know the limiting and excess reactants, now am I suppose to find the moles of Mg, H, and CI?
use simply the unitary method. the equation says, 2 moles of HCl produced 1 mole of H2 now, 1 mole of HCl will produce 0.5 mole of H2 now, 2.5 mole of HCl will produce 0.5 * 2.5 moles of H2. = 1.25moles. i hope this helps,
So if I have 2.5 moles of magnesium and 2.5 moles of HCL, 1.25 moles of hydrogen are formed?
yes.! acc to calculatins. this is the ans. i got!
ty!!!!!!!!!!!
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