Chemistry
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OpenStudy (anonymous):
You weigh out a sample of 2.45 grams of fluorine. How many atoms are in your sample? I think I have an idea of how to get it but I wanna be sure
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OpenStudy (anonymous):
@phi
OpenStudy (anonymous):
calculate the number of moles of Fluorine atom then multiply by 6.02 x 10 ^23
OpenStudy (anonymous):
ok so 2.45/18.99 g/mol=0.129 mol * (6.02*10^23)
OpenStudy (anonymous):
0.129 x 2 x 6.02 x 10^23
OpenStudy (anonymous):
ok and is 7.77*10^22 atoms of F correct?
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OpenStudy (anonymous):
where did the 2 in your equation come from @Ezizio
OpenStudy (anonymous):
what u just calculated was the number of F2 molecules
OpenStudy (anonymous):
they are asking for the number of F atoms
OpenStudy (anonymous):
yes and ! divided yours by 2 and got 7.77*10^22 atoms of F
OpenStudy (anonymous):
you need to multiply by 2
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OpenStudy (anonymous):
2.45 / 18.99 = moles of F2 molecules
OpenStudy (anonymous):
(2.45 / 18.99) x 2 = moles of F atoms
OpenStudy (anonymous):
yup, and 2.45 / 18.99 = moles of F2 molecules=0.129 mol
0.129 mol* 6.02*10^23=7.77* 10^22 atoms of F
OpenStudy (anonymous):
april sages, what you've just calculated is the number of F2 molecules
OpenStudy (anonymous):
1 mole = 6.02 x 10^ 23 particles
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OpenStudy (anonymous):
so you just found out 7.77 x 10^ 22 particles of F2
OpenStudy (anonymous):
what do u mean?
OpenStudy (anonymous):
no atoms?
OpenStudy (anonymous):
they want atom, there is a difference between atom and molecules
OpenStudy (anonymous):
ok show me how to get atoms
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OpenStudy (anonymous):
multiply your answer by 2
OpenStudy (anonymous):
so (7.77 x 10^ 22)*2
OpenStudy (anonymous):
yes, that is for number of F atoms
OpenStudy (anonymous):
so 1.554*10^23 is my final answer?
OpenStudy (anonymous):
@Ezizio
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OpenStudy (anonymous):
yes correct
OpenStudy (anonymous):
ty!!!!!!!!!!!!!!!
OpenStudy (anonymous):
np