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Chemistry 8 Online
OpenStudy (anonymous):

You weigh out a sample of 2.45 grams of fluorine. How many atoms are in your sample? My answer: 1.554*10^23 atoms of F

OpenStudy (anonymous):

what do ya'll think @texaschic101 @phi @Luigi0210

OpenStudy (anonymous):

@yrelhan4

OpenStudy (anonymous):

pleaseeeeeeeeeeeeeeee

OpenStudy (luigi0210):

2.45g/18.99g.mol = 0.129mol x (6.02x10^23) - 7.77x10^22 atoms of Fluorine I think this might be it.. I'm not sure I haven't taken chemistry in over 3 years >.<

OpenStudy (yrelhan4):

Yup, that should be right. ^

OpenStudy (yrelhan4):

basically number of atoms = moles*avagadros number and atomic mass of Fluorine is 18.99 so 2.45/18.99 gives you the moles and avagadros number of 6.022*10^23..

OpenStudy (luigi0210):

thank you for the assurance @yrelhan4 :)

OpenStudy (yrelhan4):

:)

OpenStudy (anonymous):

ty!!!!!!!!!!!!!!!!

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