Question

find the distance between 2,0 and -2,8

Answer 1

do the distance formula
\[\sqrt(x2 −x1 )^ 2 + (y2 - y1 )^2 \]

Answer 2

i get a decimal tho

Answer 3

then plug in the points (2,0) and (-2,8)
it will be\[\sqrt(-2 - 2)^2 + (8 - 0)^2 =\sqrt(-4)^2+(8)^2 \]
\[\sqrt( 16) + (64) =\sqrt (80)\]

Answer 4

so the simplified version of \[\sqrt(80) \] is \[4\sqrt(5)\]

Answer 5

thats the answer right?

Answer 6

yes thanks!

Answer 7

if you need help ask me

Answer 8

find the intercepts and use them to sketch the graph...
3y-5x=0

Answer 9

well the y intercept is going to be 3y = 5x
then y = 5/3x
and x is going to be -5x = -3y
then x = -3/-5y which will be x = 3/5y

Answer 10

and plug them in and you get the graph

Answer 11

wait no!!!!!!
I was just blanked out over there when i wrote.

Answer 12

ok wait almost got it

Answer 13

Okay, you need to find the intercepts, correct? Here's how I do it:

Set x = 0, solve for y:
3y−5(0)=0
3y=0
y=


Set y = 0, solve for x:
3(0)−5x=0
−5x=0
x=


The point where x = 0 is the y-intercept. The point where y = 0 is the x-intercept.

Answer 14

so the intercepts are (0,0)