Find sin θ if cot θ = - 4 and cos θ < 0.
us cot x =cos x / sin x
I have, and I understand that sin(x) must be positive. sin(x) must equal cos(x)/-4 right?
yes
I don't know what to do next. The multiple choice answers are: -17, sqrt(17)/17, -1/4, and sqrt(17)/4
anyone?
\[\frac{ \cos \theta }{ \sin \theta } = -4\]\[\cos \theta = -4\sin \theta\]You can substitute that expression for cos in the following:\[\cos ^{2}\theta + \sin ^{2}\theta = 1\]
\[\left( -4\sin \theta \right)^{2} + \sin ^{2}\theta = 1\]
\[16\sin ^{2}\theta + \sin ^{2}\theta = 1\]From here, you should be able to simplify and get the answer.
When simplifying, as a last step, rationalize your denominator.
Also, bear in mind that the cotangent and cosine are negative. Therefore, the sine is positive.
another approach is to use a right triangle cot = adj/opp |dw:1371496041950:dw| the hypotenuse can be found using pythagorean thm
Thanks guys!!! Really appreciate it.
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