Question

3y-5x=0

Answer 1

Okay, you need to find the intercepts, correct? Here's how I do it:

Set x = 0, solve for y:
\[3y-5(0) = 0\]\[3y=0\]\[y=\]

Set y = 0, solve for x:
\[3(0)-5x=0\]\[-5x=0\]\[x=\]

The point where x = 0 is the y-intercept. The point where y = 0 is the x-intercept.

Answer 2

so it is just (0,0)??

Answer 3

This case is perhaps a bit unusual in that the x-intercept and y-intercept are the same point — not so common...though of course there are infinitely many equations for which it is true, so it's a funny version of "not so common" :-)

Answer 4

yes, when x = 0, y = 0, and when y = 0, x = 0, so the two intercepts are (0,0) and (0,0). I imagine you already got that and scratched your head, thinking it must be incorrect, right?

Answer 5

ok i get it thanks

Answer 6

A more typical case would be something like 3y -5x = 1, and there the intercepts would be different:

3(0)-5x=1, x = -1/5, so x-intercept of (-1/5,0)
3y-5(0)=1, y = 1/3, so y-intercept of (0,1/3)