Question

Solve: 112=-16t^2+128t

Answer 1

I know you get two separate answers but I'm not sure the steps to get there.

Answer 2

can you bring that in the form of
\(ax^2+bx+c = 0 \)

Answer 3

by adding 16t^2-128t on both sides.

Answer 4

yes so, -16t^2+128t-112=0 or -16t^2-128t+112

Answer 5

sorry i forgot the =0 on the second one

Answer 6

ok, you brought 112 on other side, -16t^2 +128t-112 =0 is correct, but how about
16t^2 -128t+112 = 0 ?

Answer 7

wouldn't you get the same answer?

Answer 8

ofcourse !
and now can you simplify that a bit before proceeding ?
notice that you can divide the entire equation by 16 and make those large numbers like 128,112....small

Answer 9

16t^2 -16*8t +16*7 =0 ----->t^2 -8t +7=0
got this ?

Answer 10

yes that's what i got

Answer 11

t^2 -8t +7=0 is relatively simple to solve
can you think of 2 numbers whose product is 7
and sum is -8 ??

Answer 12

that would factor out to (t-7) (t-1) right?

Answer 13

absolutely correct :)

Answer 14

(t-7) (t-1) =0
gives you which 2 values of t ?

Answer 15

1 and 7?

Answer 16

good! thats your answer :)

Answer 17

THANK YOU!

Answer 18

welcome ^_^