Question

Find all solutions to the equation.

7 sin2x - 14 sin x + 2 = -5

Answer 1

\[\sin ^ {2}x or sinx\]

Answer 2

could this be \(7\sin^2(x)-14\sin(x)+2=-7\)?

Answer 3

yea, sorry

Answer 4

sinx=1

Answer 5

start with
\[7\sin^2(x)-14\sin(x)+7=0\] then divide by 7 and get
\[\sin^2(x)-2\sin(x)=1\] a perfect square
this gives
\[(\sin(x)-1)^2-0\] and so \[\sin(x)=1\]

Answer 6

Oh! Seems simple enough:) thanks

Answer 7

i made a typo, should have written
\[\sin^2(x)-2\sin(x)-1=0\]