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x2-6x+6=0
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Use the quadratic formula, I dont think that factors
\[\frac{ 6 \pm \sqrt{(-6)^2 -4(1)(6)} }{ 2(1) }\] set it up for you
thanks boys
\[\large x= \frac{-b \pm \sqrt{b^2 -4ac}}{2a}\]\[\large x= \frac{-(-6) \pm \sqrt{(-6)^2 -4(1)(6)}}{2(1)}\]\[\large x= \frac{+6 \pm \sqrt{36 -24}}{2}\]\[\large x= \frac{6\pm 2\sqrt{3}}{2}\] x will have 2 values. \[\large x= 3 + \sqrt{3} \ \ \ \text{or} \ \ \ x= 3-\sqrt{3}\]
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