Question

how do you determine the zeros of the function f(x) = 4x2 + 4x - 3?

Answer 1

minuto

Answer 2

$$
\text{make y=0}\\
0=4x^2 + 4x - 3 \implies 0 = \color{blue}{ax^2+bx-c}\\
\text{using the quadratic formula}\\
x = \color{blue}{\cfrac{-b\pm\sqrt{b^2-4ac}}{2a}}
$$
it'd give you 2 values from the \(\pm addition/substraction of the root
those 2 values, are the "zeros" or also called "roots" of the function
which is really pretty much where the function "touches" the "x-axis"

Answer 3

so the zeros above, is where the function "touches" the x-axis