Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

What is the length of the hypotenuse of the triangle below?

OpenStudy (anonymous):

|dw:1371516403250:dw|

OpenStudy (anonymous):

\[a^2+b^2=c^2\]

OpenStudy (anonymous):

try to solve it

OpenStudy (anonymous):

if you still have trouble i can help

OpenStudy (anonymous):

\[9^2+9^2=c^2\]

OpenStudy (anonymous):

So you get 162

OpenStudy (anonymous):

Yes. Very good job.

jimthompson5910 (jim_thompson5910):

a and b are 9*sqrt(2) not just 9

OpenStudy (anonymous):

That is what i wrote

jimthompson5910 (jim_thompson5910):

9^2 isn't the same as 9*sqrt(2) though

OpenStudy (anonymous):

Jim is correct. The drawing has each leg labeled as \(9\sqrt{2}\). Your work treats each leg as only 9.

OpenStudy (anonymous):

So it would be \[81^2\]?

OpenStudy (anonymous):

Her approach is good though, Stephanie. If you have a right triangle and you know two of the three sides, plug the sides into \(a^2+b^2 = c^c\) and solve for the third side. Make sure the longest side is plugged into c in your equation.

OpenStudy (goldphenoix):

\[\large \large (9\sqrt{2}^2) + (9\sqrt{2}^2) = h^2\]

OpenStudy (anonymous):

Actually, no @GoldPhenoix \(\Large (9\sqrt{2})^2 + (9\sqrt{2})^2 = h^2\) And \(\Large (9\sqrt{2})^2\) simplifies to \(\Large9^2*\sqrt{2}^2\)

OpenStudy (goldphenoix):

My bad. I thought my exponent was outside the parenthesis. =/

OpenStudy (anonymous):

Easy mistake to make =)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!