Question

s sec^3x tan^3x dx

Answer 1

write everything in terms of secant, leaving a \(\sec(x)\tan(x)\) behind
then use a u - sub

Answer 2

\[\sec^2(x)\tan^2(x)\sec(x)\tan(x)\] is the first step

Answer 3

then use \(\tan^2(x)=\sec^2(x)-1\) to write it as
\[\sec^2(x)(\sec^2(x)-1)\sec(x)\tan(x)\]

Answer 4

or
\[\left(\sec^4(x)-\sec^2(x)\right)(\sec(x)\tan(x))\]

Answer 5

then the u-sub with \(u=\sec(x), du =\sec(x)\tan(x)\) should finish it

Answer 6

thank you

Answer 7

yw