Mathematics
11 Online
OpenStudy (anonymous):
a circle has a radius of 6 in. The inscribed equilateral triangle will have an area of?
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OpenStudy (anonymous):
ok. i got it
OpenStudy (jhannybean):
Helpmeeeeee
OpenStudy (anonymous):
Each edge of the equilateral triangle is a equal sized chord of the circle.
central angle of 120
OpenStudy (anonymous):
now what is the formula for chord length?
OpenStudy (anonymous):
there are 2 ways of doing this
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OpenStudy (jhannybean):
umm...
OpenStudy (anonymous):
k heres the easier way
OpenStudy (anonymous):
use a dbl integreal lol.
OpenStudy (jhannybean):
Ohh my radius...
OpenStudy (anonymous):
Split the equilateral triangle into 3 separate isosceles tri
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OpenStudy (jhannybean):
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OpenStudy (anonymous):
i need some paper. gimmi a tic
OpenStudy (anonymous):
good!
OpenStudy (jhannybean):
IM GETTING THIS.
OpenStudy (anonymous):
In each isosceles triangle there is then one 120 ° angle and two 30 ° angles.
Equal sides are 6 in long
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OpenStudy (anonymous):
with a polar coordinate system :D
OpenStudy (jhannybean):
ohh that's right.
OpenStudy (jhannybean):
Hush timo, you're making it complicated >:(
OpenStudy (anonymous):
now just use co-sine rule
OpenStudy (jhannybean):
xD
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OpenStudy (anonymous):
SIK!
OpenStudy (anonymous):
tell me wat u get
OpenStudy (jhannybean):
ugh, law of cosines?
OpenStudy (anonymous):
that is what awaits you in calc 3! MUAHAHA!
OpenStudy (anonymous):
@Jhannybean
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OpenStudy (anonymous):
yep
OpenStudy (jhannybean):
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OpenStudy (anonymous):
i stop maths after 2nd yr.
OpenStudy (anonymous):
kk use cosine rule
OpenStudy (jhannybean):
cosine rue....lemme look that up really fast. DONT SAY IT.
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OpenStudy (anonymous):
haha ok
OpenStudy (jhannybean):
\[\large c^2 = a^2 +b^2 -2abcos(C)\]\[\large c^2 = 6^2 +6^2 -2(6)(6)\cos(120)\]\[\large c = \sqrt{6^2+6^2 -2(36)(\cos(120))}\]\[\large C \approx 10.40\]
OpenStudy (anonymous):
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