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Mathematics 11 Online
OpenStudy (anonymous):

a circle has a radius of 6 in. The inscribed equilateral triangle will have an area of?

OpenStudy (anonymous):

ok. i got it

OpenStudy (jhannybean):

Helpmeeeeee

OpenStudy (anonymous):

Each edge of the equilateral triangle is a equal sized chord of the circle. central angle of 120

OpenStudy (anonymous):

now what is the formula for chord length?

OpenStudy (anonymous):

there are 2 ways of doing this

OpenStudy (jhannybean):

umm...

OpenStudy (anonymous):

k heres the easier way

OpenStudy (anonymous):

use a dbl integreal lol.

OpenStudy (jhannybean):

Ohh my radius...

OpenStudy (anonymous):

Split the equilateral triangle into 3 separate isosceles tri

OpenStudy (jhannybean):

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OpenStudy (anonymous):

i need some paper. gimmi a tic

OpenStudy (anonymous):

good!

OpenStudy (jhannybean):

IM GETTING THIS.

OpenStudy (anonymous):

In each isosceles triangle there is then one 120 ° angle and two 30 ° angles. Equal sides are 6 in long

OpenStudy (anonymous):

with a polar coordinate system :D

OpenStudy (jhannybean):

ohh that's right.

OpenStudy (jhannybean):

Hush timo, you're making it complicated >:(

OpenStudy (anonymous):

now just use co-sine rule

OpenStudy (jhannybean):

xD

OpenStudy (anonymous):

SIK!

OpenStudy (anonymous):

tell me wat u get

OpenStudy (jhannybean):

ugh, law of cosines?

OpenStudy (anonymous):

that is what awaits you in calc 3! MUAHAHA!

OpenStudy (anonymous):

@Jhannybean

OpenStudy (anonymous):

yep

OpenStudy (jhannybean):

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OpenStudy (anonymous):

i stop maths after 2nd yr.

OpenStudy (anonymous):

kk use cosine rule

OpenStudy (jhannybean):

cosine rue....lemme look that up really fast. DONT SAY IT.

OpenStudy (anonymous):

haha ok

OpenStudy (jhannybean):

\[\large c^2 = a^2 +b^2 -2abcos(C)\]\[\large c^2 = 6^2 +6^2 -2(6)(6)\cos(120)\]\[\large c = \sqrt{6^2+6^2 -2(36)(\cos(120))}\]\[\large C \approx 10.40\]

OpenStudy (anonymous):

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