Use the Rational Zeros Theorem to write a list of all possible rational zeros of the function. f(x) = -2x4 + 4x3 + 3x2 + 18 Show work to receive credit.
1. find all factors of leading coefficient 2. find all factors of constant term
how would I find the factors of leading coefficient and constant term?
wats the leading coefficent here ?
-2?
is it?
yes. so factors are just \(\pm 1, \pm 2\)
similarly find factors for constant term also
ok so 1 and 2 are possible rational zeros of the function?
nope we're not finished yet.
Find factors of constant term, them we can figure out the possible rational roots
*then
are the factors of the constant term 1,2, and 4?
you missed a few
and 4 is not a factor of 18. 4 doesnt divide 19
factors of a number are just all the numbers that divide it.
for ex, 9 is a factor of 18, cuz 9 divides 18
so its 1 2 and 3 then in this case
thats all ?
factors of 18 : \(\pm 1 , \pm 2, \pm 3, \pm 6, \pm 9, \pm 18\)
so since we have all the factors for the function, do we start finding the possible rational zeros for the function?
yes, possible rational zeroes are just the fraction of factors of 'constant term' and 'leading coeffecient'
oh ok. can you draw it out so I can see the work better? if you can, that'd be nice
factors of constant term : \(\pm 1 , \pm 2, \pm 3, \pm 6, \pm 9, \pm 18 \) factors of leading coeff : \(\pm 1 , \pm 2\) possible rational zeroes : \(\pm\frac{1}{1},\pm\frac{2}{1},\pm\frac{3}{1},\pm\frac{6}{1},\pm\frac{9}{1},\pm\frac{18}{1} \) and, \(\pm\frac{1}{2},\pm\frac{2}{2},\pm\frac{3}{2},\pm\frac{6}{2},\pm\frac{9}{2},\pm\frac{18}{2} \)
simplify the fractions
so the simplified fractions would be: 1, 2, 3, 6, 9, and 18 as well as 1/2, 1, 3/2, 3, 9/2, and 9. is this right?
thats right, arrange them in order
possible rational zeroes : \(\pm 1/2, \pm 1, \pm 3/2, \pm 3, \pm 9/2, \pm 6, \pm 9, \pm 18\)
dont forget the negative ones !
oh ok and thank you so much! and I won't
np :)
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