Question

two bags each contain blue marbles and black marbles. the first contains 4 blue marbles and 6 black marbles and the second bag contains 6 blue marbles and 6 black marbles. a marble is randomly drawn from each bag. what is the probability that both marbles are blue?
a. 1/5
b. 1/12
c. 3/10
d. 1/10

Answer 1

the first bag have 4 blues and 6 blacks, so probability would be 4/10 = 2/5
the second bag have 6 blues and 6 blacks, so probability would be 6/12 = 1/2
multiply 2/5 . 1/2

Answer 2

i got 0.2 .-.

Answer 3

2 1 2 1
-- x --- = ----- = ----
5 2 10 5

Answer 4

.2 is the same as 1/5

Answer 5

thanks, :) since your already helping me with this one can you help me with another one of these? please? :c

Answer 6

sure

Answer 7

two bags each contain white marbles and yellow marbles. the first contains 6 white marbles and 5 yellow marbles and the second bag contains 4 white marbles and 3 yellow marbles. a marble is randomly drawn from each bag. what is the probability that both are yellow?

a. 15/77
b. 18/33
c. 10/77
d. 24/77

Answer 8

i think it's A because i did exactly what you did on the other ;P

Answer 9

that is a similar questions,
you have first bag = 6 white and 5 yellows = total altogether = 11
second bag: 4 white and 3 yellows: total 7
so probability of yellow on first bag 5/11
second bag = 3/7

Answer 10

now multiply both fractions

Answer 11

i got it, thanks :D

Answer 12

yw :)

Answer 13

34 brown marbles and a big purple bowling ball

Answer 14

The probability of drawing 3 red marbles in a row from a bag of 3 blue and 4 red marbles without replacement is right at about 0.11 or about 11 in 100, if you want odds.
Remember that probability is a pure number between zero (no chance - it's impossible) and 1 (it will happen - it's a certainty). A probability of 0.5 is a 50-50 shot, like a coin toss. We good? Let's move on.
We have 7 marbles, and there is a 4 in 7 shot of getting a red marble in the first draw. There is a 3 in 6 shot the next draw since now we only have 6 marbles total (NO replacement) and only 3 red ones (we already drew a red one out). Similarly, there is a 2 in 5 shot of getting a third red one if the first two are red. The probability of the first action (getting a red marble on the first draw) is 4/7 or a probability of about 0.5714. Second draw, it's 3/6 or a probability of 0.5. Last, it's 2/5 or a probability of 0.40. To find the intersection of these probabilities, we just multiply them all together, and we'll get right at about 0.011 for a probability.
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