Question

Solve~

Answer 1

Remember subtraction is division in logarithms!

Answer 2

you would have to know that for log of the same bases subtracting
\[\Large \log_ax-\log_ay=\lg_a(\frac{ x }{ y })\]

Answer 3

so using that, you now have
\[\Large \log_8(\frac{ x+2 }{ x-1 })=\frac{ 2 }{ 3 }\]

Answer 4

Buy a log book damn ;D

Answer 5

XD

Answer 6

also, using the definition of log which says that
\[\large \log_ax=b~~~{\mathbb{is~~ the ~~same~~ as~~ writing}}~~x=a^b\]
so using that,
\[\Large \frac{ x +2}{ x-1 }=8^{\frac{ 2 }{ 3 }}\]
hope you can continue from there