Factor a3 - 3 + 3a2 - a.
HELP!!
A. (a - 1)(a + 1)(a + 3)
B. (a2+ 1)(a - 3)
C. (a2- 3)(a + 1)
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OpenStudy (anonymous):
You should definitely put it in standard form as the first step.
OpenStudy (anonymous):
ok
OpenStudy (whpalmer4):
This can be done by "factoring by grouping". Let's write it out in standard form, as suggested:
\[a^3+3a^2-a-3\]
Now we'll group it into two chunks:
\[(a^3+3a^2)-1(a+3)\]
Notice that I pulled out a -1 from the last two terms. The reason why will become apparent shortly.
OpenStudy (whpalmer4):
Now can you factor the first group at all? \((a^3+3a^2)\)
OpenStudy (whpalmer4):
What is the largest common factor of \(a^3+3a^2\)?
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OpenStudy (anonymous):
idk
OpenStudy (anonymous):
Find the largest item that is common in both of the items..
OpenStudy (whpalmer4):
Here, let's write it as \[a^3+3a^2 = a*a*a + 3*a*a\]
OpenStudy (anonymous):
^ Exactly
OpenStudy (whpalmer4):
Remember the distributive property? \[x(y+z) = x*y + x*z\]We're trying to do that in reverse.
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OpenStudy (whpalmer4):
We've got \(x*y + x*z\) and we want to split it back into \( x (y+z)\)