Factor a3 - 3 + 3a2 - a. HELP!! A. (a - 1)(a + 1)(a + 3) B. (a2+ 1)(a - 3) C. (a2- 3)(a + 1)
You should definitely put it in standard form as the first step.
ok
This can be done by "factoring by grouping". Let's write it out in standard form, as suggested: \[a^3+3a^2-a-3\] Now we'll group it into two chunks: \[(a^3+3a^2)-1(a+3)\] Notice that I pulled out a -1 from the last two terms. The reason why will become apparent shortly.
Now can you factor the first group at all? \((a^3+3a^2)\)
What is the largest common factor of \(a^3+3a^2\)?
idk
Find the largest item that is common in both of the items..
Here, let's write it as \[a^3+3a^2 = a*a*a + 3*a*a\]
^ Exactly
Remember the distributive property? \[x(y+z) = x*y + x*z\]We're trying to do that in reverse.
We've got \(x*y + x*z\) and we want to split it back into \( x (y+z)\)
Join our real-time social learning platform and learn together with your friends!