Question

how to find the restriction of 9x^2-25/3x-5

Answer 1

what do you mean by restriction?

Answer 2

you need to find what values x can not assume,

there are a few rules for this, amoung them are that sqaure roots can not be negative, and (for example here) the denominator can not have a 0 in a fraction.

Answer 3

i simplify the problem to 3x+5 but then it asks for restrictions
either 5/3 or -5/3

Answer 4

what's a restriction?

Answer 5

i think it is what x cannot equal

Answer 6

but i have no idea how to find it

Answer 7

yes, remember that the decominator can NOT be zero
so you need to when 3x + 5 = 0
after you find that x value that is what x can not assume

Answer 8

oh so it equals -5/3 then?

Answer 9

do you always find the restriction after you simplify the problem?

Answer 10

yes, what "x" mustn't be

in this case you have a fraction, a rational,
0/5 = 0
0/215 = 0
5/0 = undefined
215/0 = undefined


so, you cannot have a 0 in the denominator for a fraction to yield a valid value

Answer 11

you don't apply the restriction to the simplified version, it always applies to the original one

Answer 12

you find the restriction BEFORE you simply the problem

Answer 13

from the numerator?

Answer 14

set the numerator equal to zero?

Answer 15

if you simply the problem you find that it is just the equation of a line. this type of problem has a removeable discontinuity (AKA hole). so it would look something like this.

Answer 16

the only restriction on fractions is that the denominator can not equal 0. the numerator can be 0 though.

Answer 17

i see what your saying, thanks alot