Question

what is the length of leg s in the triangle

Answer 1

same thing, use pythagoras theorem
or the fact that in 45-45-90 triangle, legs * sqrt 2 = hypotenuse
here, legs = s = to be found
hypotenuse = 8 root 2

Answer 2

so i would do 8√2 and?

Answer 3

first tell me what u prefer ? pythagoras or legs * sqrt 2 = hypotenuse ?

Answer 4

pythagoras seems more easier for me to understand

Answer 5

then a^2+b^2 =c^2
a, b are legs, both = s,
c= hypotenuse = 8 sqrt 2
plug in these!

Answer 6

\((8\sqrt2)^2=....?\)

Answer 7

16

Answer 8

16 ? no.....what u got as 16 ?

Answer 9

8√2^2=16

Answer 10

actually,
\((\sqrt2)^2 =\sqrt2\times \sqrt2=2\)
and \((8\sqrt2)^2=8^2(\sqrt2)^2=.....?\)

Answer 11

so i would do the equation 8^2(√2^2?

Answer 12

pythagoras :
\(s^2+s^2 = (8\sqrt2)^2\)
first did u get this ?

Answer 13

yes

Answer 14

so, can u find s from there ?

Answer 15

im still kinda confused

Answer 16

\(s^2+s^2 = (8\sqrt2)^2 \\ 2s^2 =8^2*2\)
got this step ?

Answer 17

okay yes

Answer 18

notice the 2's are getting cancelled,
now can u find s ?

Answer 19

hmmm

Answer 20

I dont know

Answer 21

s^2 = 8^2
s= 8
by taking square root on both sides...

Answer 22

now here's a shortcut :
legs * sqrt 2 = hypotenuse
s* sqrt 2 = 8*sqrt 2
s=8
(cancelling sqrt 2)

Answer 23

oh now i get it! this equation actually made more sense

Answer 24

great! :)