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Question

>,<   what is the answer for this..

pradius · Answer

$$3X+3\left| X-1 \right|=6$$

jdoe0001 · Answer

first isolate the absolute value term, what do you end up with?

dumbcow · Answer

isolate absolute value
$$|x-1| = 2-x$$
split into 2 cases
positive case:
$$x-1 = 2-x$$
$$x = \frac{3}{2}$$
neg case
$$x-1 = -(2-x)$$
$$x-1 = x-2$$
impossible, thus No solution

pradius · Answer

I just want to know if the solutions is  1  both when $$\left| X-1 \right|$$ is X-1 and -(X-1)

jdoe0001 · Answer

as you can see from dumbcow's two cases, one has a value, one fell through

pradius · Answer

wait ..now Im completely lost... worst than before.. where did u get that 2-x from?

anonymous · Answer

this is hard :/

pradius · Answer

no its not! lol.. I just wasnt in class that day,,

dumbcow · Answer

sorry didn't mean to confuse you...just solved for the abs value
"2-x" is what you end up with after simplifying
$$3|x-1| = 6-3x$$
divide by 3
$$|x-1| = \frac{6-3x}{3}$$
$$|x-1| = 2-x$$

pradius · Answer

I thought u get  x-1= 3x+ 3 when u isolate the absolute value

pradius · Answer

ohhh so I shud treat it like a multiplication...  grrr...

dumbcow · Answer

haha yeah....3|x-1| is 3*|x-1|
is that what you mean

pradius · Answer

yep exactly.. that was the problem..  Thanks!!

dumbcow · Answer

yw