What are the zeros of the polynomial function: f(x) = x3 – 5x2 + 6x ?
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OpenStudy (loser66):
factor x out first, tell me what you have
OpenStudy (anonymous):
what do you mean ?
OpenStudy (loser66):
oh, sorry, I don't know what I mean, too. let me tag other for help. @Jhannybean
OpenStudy (jhannybean):
Fator out an x first. you see that there is a common "x" multiplier in this function, so pull out out of all the terms. You would have
\[\large f(x) = x^3 - 5x^2 +6x \]\[\large f(x) = x(x^2 -5x +6)=0\] Can you finish this up now? :)
OpenStudy (anonymous):
What do i do ? :()
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OpenStudy (jhannybean):
what are two numbers that multiply to get 6, but add to give you -5?
OpenStudy (jhannybean):
hint: think of the multiples of 6.
OpenStudy (anonymous):
(x-3)(x-2)
OpenStudy (jhannybean):
good. so now you have 3 terms to solve for.
x = 0
x - 3 = 0
x - 2 = 0
Can you find the zeroes of your function?
OpenStudy (anonymous):
so 3 and 2 ?
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OpenStudy (jhannybean):
and 1 more
OpenStudy (anonymous):
oopss 0 , 3 , 2
OpenStudy (jhannybean):
Yay! you got it.
OpenStudy (anonymous):
ok . one more ?
OpenStudy (anonymous):
According to The Fundamental Theorem of Algebra, how many zeros does the function f(x) = 24x5 + 8x3 – 2x – 15 have?
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OpenStudy (jhannybean):
To find this, analyze the variable with the highest power.
OpenStudy (anonymous):
24
OpenStudy (jhannybean):
no the power, not the coefficient. \[\large f(x) =24\color{green}{x^5}+8x^3-2x-15 \]
OpenStudy (anonymous):
so its 5 ?
OpenStudy (anonymous):
hello ?
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