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Evaluate 9P5. 15,120 45 362,880
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In general\[P(n,k) = \frac{n!}{(n-k)!}\]Here you have n=9, k=5
45?
It would be\[\frac{9!}{(9-5)!} = \frac{9!}{4!} = \frac{1*2*3*4*5*6*7*8*9}{1*2*3*4}\]
?
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?
no?
i am really confused
Simplify this \[\frac{1*2*3*4*5*6*7*8*9}{1*2*3*4}\] where * denotes multiplication. This can't get any simpler.
k thanks i got it now
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its the last one
If you do the multiplication, you will find the correct answer.
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