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Calculus1 21 Online
OpenStudy (anonymous):

Limits

OpenStudy (anonymous):

\[\lim_{x \rightarrow 3}x+2\div x-3\]

OpenStudy (anonymous):

I know the answer is that the limit DNE... why?

OpenStudy (anonymous):

the way you have it written does not make sense are you sure its not \[\lim_{x \rightarrow 3^+} \frac{x+2}{x-3}\]

OpenStudy (anonymous):

er sorry, without the +

OpenStudy (anonymous):

that is how the problem, is my bad. i couldn't figure out how to type it as such.

OpenStudy (anonymous):

just a note for the future use frac{ a} {b} to get a/b

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

in order for a limit to exist, you need to evaluate the limit from the left and the limit from the right if the limits are the same, then the limit exists and is that number if the limits are different, then no limit exists at that point

OpenStudy (anonymous):

i know that; i guess i'm stuck on how to evaluate it from each side??

OpenStudy (anonymous):

ok, if x is approaching 3 from the left side , the answer is negative infinity , x is approaching from the right side, the answer is positive infinity, the answer is DNE

OpenStudy (anonymous):

from the right, use a value like 3.00000001 from the left, use a value like 2.99999999

OpenStudy (anonymous):

yes, image 3.000001-3 then the answer will be positive infinity, 2.99999999-3, the answer will be negative infinity

OpenStudy (anonymous):

OKAY, i was using really small decimals around 0, not 3. i'm an idiot. okay. thanks!

OpenStudy (anonymous):

no prob

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