Simplify (x^-2/5y^1/3)^15 x^6y^5 x^6/y^5 y^5/x^6 1/x^6y^5
\[\huge \left( \frac{\frac{x^{-2}}{5y^1}}{3}\right)^{15}\] Is this it?
yes
(x^2y)^-15
which means (1) / [(x^30)(y^15)]
u got it?
yes thank you
u need th others simplified too?
no
oh my im so sorry about this.. I had written the question incorrectly the actual answer is [1/15x^2y]^15
\[[\frac{ 1 }{ 15x^2y }]^(15)\]
\[\huge \left( \frac{\frac{x^{-2}}{5y^1}}{3}\right)^{15}\] First simplify the stuff inside the parenthesis \[\large \left(\frac{x^{-2}}{15y}\right)^{15}\]distribute the 15 to everything in the numerator and denominator \[\large \left( \frac{x^{(-2\cdot 15)}}{(15 \cdot 15)y^{15}}\right)\] simplify \[\large \left( \frac{x^{-30}}{225\cdot y^{15}}\right)\] \[\large\left( \frac{1}{225 \cdot x^{30} \cdot y^{15}}\right)\]
@chrissy401 is what you've written to the 15th power?
i wrote the entire thing to the 15th power so as not to confuse the equation
If i brought in the power.. We would get the same answer
\[\large \left(\frac{1}{15x^2y}\right)^{15} = \left( \frac{1}{(15^{15})(x^{30})(y^{15})}\right)\]\[\large 15^{15} \neq (15\cdot 15)\] I solved it the wrong way as well.
yeah.. this is why i never bring in powers.. i like leaving them in the raw form.. I would have preferred to leave it like this \[\left[ 15x^2y \right]^(-15)\]
Join our real-time social learning platform and learn together with your friends!