find the derivative (x^4 + 3x^2 -2) ^5
Do you know the chain rule?
chain rule for this one \[\frac{d}{dx}[f^5(x)]=5f(x)\times f'(x)\]
so far i have 5(x^4+3x^2-2)^4 * (4x^3+6x)
i dont know how to keep going from there
i would stop
i need to fully simplify it completely
That is fully simplified. If your problem said to expand it, well, the highest order term in that sucker after expansion is \(x^{19}\) (!)
yeah there is no way in hell you want to multiply this out plus, there is no such mathematical operation as "simplify" this is a simple as it gets
find the derivative (x^4 + 3x^2 -2) ^5 f'(x)=5(x^4+3x^2-2)^4(4x^3+6x)
yeah i need to expand it.
Okay, if you want to check your work, here's what it expands to: \[2560 x^3+3600 x^5+1520 x^7-4770 x^9-1140 x^{11}+2100 x^{13}+1280 x^{15}+270 x^{17}\] plus at least one term lopped off each end so no one complains that I gave you the answer to a ridiculous problem...
thank you
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