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OpenStudy (anonymous):
SAT question: If x=5y^(t+1) and y does not equal zero, then x/y= ?
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OpenStudy (anonymous):
one not very satisfactory answer is \(\frac{x}{y}=5y^t\)
OpenStudy (anonymous):
the answer choices are:
a. 5y
b. y^t
c. y^t/5
d. 5y^t
e. 5y^(t+2)
sorry, completely forgot about typing the answer choices @satellite73
OpenStudy (anonymous):
then i would go with D
OpenStudy (mertsj):
Just like @satellite73 said....D
OpenStudy (anonymous):
\[x=5y^{t+1}=5y^t\times y\] so
\[\frac{x}{y}=5y^t\]
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OpenStudy (anonymous):
@satellite73 where does the +1 go when you split it up?
OpenStudy (anonymous):
D.
OpenStudy (anonymous):
\(b^{n}{b^m}=b^{m+n}\)
OpenStudy (anonymous):
so \(y^{t+1}=y^ty\)
OpenStudy (anonymous):
@satellite73 Why is it 5y^t and not 5y^t x y ?
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OpenStudy (anonymous):
you lost me
OpenStudy (anonymous):
And how is that the answer overall? I don't see the link between the answer and x/y. Sorry for the hassle
OpenStudy (anonymous):
ok lets go slow
OpenStudy (anonymous):
\[x=5y^{t+1}\] is what is given
OpenStudy (anonymous):
that is the same as saying
\[x=5y^t\times y\] since \(y^t\times y=y^{t+1}\)
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OpenStudy (anonymous):
then if you divide both sides by \(y\) you get
\[\frac{x}{y}=\frac{5y^t\times \cancel{y}}{\cancel{y}}=5y^t\]
OpenStudy (anonymous):
@satellite73 How do you know that 5y^t x y is the numerator?
OpenStudy (anonymous):
OH okay NEVERMINd
OpenStudy (anonymous):
ok
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