Question

Implicit Differentiation. x^3 +y^3 =24xy.

Answer 1

I ended up with, but its not correct. Not sure what i did wrong.

\[y'= \frac{ -3x+24y }{ 3y-24x} \]

Answer 2

Woops i ignored the squares....

Answer 3

https://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/implicitdiffdirectory/

Answer 4

\[\large x^3 +y^3 = 24xy\]\[\large \frac{dx}{dy} = 3x^2 + 3y^2 y' = 24(y +xy')\]

Answer 5

3x^2+3y^2(dy/dx)=24(x dy/dx + y)

Answer 6

xD

Answer 7

I caught my own mistake on this one.

Answer 8

aw too slow on my phone

Answer 9

Mwuahahaha

Answer 10

I'm to tired for this, been doing calc all day lol. Sorry. Thanks for the race responses though : )

Answer 11

\[\large \frac{dx}{dy} = 3x^2 + 3y^2 y' = 24(y +xy')\]\[\large 3x^2 y' -24xy' = 24y -3x^2 \]\[\large y' = \frac{24y - 3x^2}{3x^2 -24y}\]

Answer 12

Then divide out 3 from everything to simplify. I got it!!

Answer 13

\[\large y' = \frac{24y - 3x^2}{3x^2 -24y}\]\[\large y'=\frac{8y -x^2}{x^2 -8y}\]

Answer 14

Yup yup!