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Mathematics 10 Online
OpenStudy (anonymous):

what is the vertical asymptote of x^3/x^4-81

OpenStudy (dumbcow):

set denominator equal to 0

OpenStudy (anonymous):

so it would be 9 &-9?

OpenStudy (luigi0210):

if it was x^2=81 then yes

OpenStudy (anonymous):

well what do i do since its x^4?

OpenStudy (dumbcow):

take 4th root of 81 .... +-3

OpenStudy (anonymous):

so thats my answer?

OpenStudy (dumbcow):

vertical asymptotes are imaginary vertical lines designated by equations "x = ?" answers are: x = 3 x = -3 again looking at the graph would greatly help...i assume you have a graphing calculator http://www.wolframalpha.com/input/?i=plot+x%5E3%2F%28x%5E4-81%29+from+-6+to+6

OpenStudy (anonymous):

how do i find horizontal asymptotes?

OpenStudy (dumbcow):

well one... look at graph , what does curve approach as x-> infinity ? also the rule is if degree on bottom > degree on top ..... horizontal is y=0

OpenStudy (anonymous):

oh okay i understand i figured that. one more question.what is the domain of 4(x^2-100)

OpenStudy (dumbcow):

domain is everything except the vertical asymptotes....so basically this question is find the vertical asymptotes

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