Question

What is the location of this parabola's focal point?

y = (1/4)(x – 400)2

Answer 1

p is distance from vertex to focus
\[p = \frac{1}{4a}\]
where
\[y = a(x-h)^{2} +k\]
so plug in "a" to find "p"
then add that to coord of vertex

Answer 2

but what is a @dumbcow

Answer 3

its the coefficient in front of (x-400)^2 term
hence the general parabola equation
\[y = a(x-h)^{2} +k\]

Answer 4

y=1/4(x-h)^2+k then?

Answer 5

no sorry im confusing you ...
im giving the general form...your equation is
\[y = \frac{1}{4}(x-400)^{2}\]
these numbers correspond to coefficient in general form
a = 1/4
h = 400
k=0

Answer 6

Oh okay @dumbcow

Answer 7

I need to have the answer in an ordered pair, though @dumbcow

Answer 8

focus is always directly above or below the vertex ... if its a function of "x"
so "x-coord" is same as vertex

Answer 9

vertex: (h,k)

thus

focus: (h, k+p)

Answer 10

@dumbcow thank you

Answer 11

your welcome