Mathematics
7 Online
OpenStudy (anonymous):
PLEASE HELP !!)
Find the length of AH for which MATH is a parallelogram.
A.
3
B.
4
C.
6
D.
10
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
|dw:1371626270516:dw|
OpenStudy (anonymous):
5f-17=90 ?
OpenStudy (anonymous):
where did 90 come from?
OpenStudy (anonymous):
idk. nvm. so how is it done?
OpenStudy (anonymous):
5f - 17 = 2f-5
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
solve for f
OpenStudy (mayankdevnani):
it is because the diagonals of parallelogram bisect each other
OpenStudy (anonymous):
yes
OpenStudy (mayankdevnani):
|dw:1371626508639:dw|
OpenStudy (anonymous):
i have about 4 minutes to solve this.. could anyone help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes?
OpenStudy (anonymous):
5f - 17 = 2f-5
solve for f
OpenStudy (anonymous):
f=4!
OpenStudy (anonymous):
plug that in to 5f - 17
OpenStudy (mayankdevnani):
you are correct!! @ashleyvee
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
5 * (4) - 17
OpenStudy (anonymous):
it said i got that answer wrong.. so it isnt 4??
OpenStudy (anonymous):
no.. listen to what i am saying
OpenStudy (anonymous):
it was 3
OpenStudy (mayankdevnani):
hey!! its f=4 not length of AH
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
4 is f... plug f into 5f - 17 you get 3
OpenStudy (anonymous):
3 is the length of PH... which is 1/2 of AH
OpenStudy (anonymous):
so AH is 6
OpenStudy (anonymous):
it's easier if you try to understand it than only caring about answers
in my experience at least
OpenStudy (mayankdevnani):
now add:
\[\huge 5f-17+2f-5\]
and plug f=4
\[\huge 5(4)-17+2(4)-5\]
can you solve it???
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mayankdevnani):
@ashleyvee