Question

(Anyone pls help?)
Quadrilateral LMNO has diagonals that intersect at point P. If LP=NP, MP = y + 25, and OP = 5y + 29, find the length of MO such that LMNO is a parallelogram.

A.24
B.48
C.61
D.122

Answer 1

For a parallelogram we have \(MP=OP\) i.e. \(y+25=5y+29\). Can you solve for \(y\) (it's trivial)? Once you do, find \(MO=MP+OP=2(y+25)=\dots\)

Answer 2

-1

Answer 3

the answers 24. Hey thanks!

Answer 4

\(y=-1\) so we get \(MO=2(24)=48\)!

Answer 5

\(24\) is just the length of *half* of \(MO\)!