Question

Operation on functions: f(x)=1/2x g(x)=4/x+12

Answer 1

What operation?

Answer 2

the suspense is killing me

Answer 3

all,,xD

Answer 4

sum diff product quo

Answer 5

oh well, I have faith in you...
maybe you've already done sum and difference? :D

Answer 6

nope. hahahahahha.. Tanga ako bro. :)))))

Answer 7

i never really liked math, xD

Answer 8

Just to rid ourselves of ambiguities,
\[f(x) = \frac12x\]
\[g(x) = \frac4x + 12\]

Are these correct?

Answer 9

nope x +12 on the denomenator,

Answer 10

Okay...
\[\Large g(x) = \frac4{x+12}\]

Answer 11

yup

Answer 12

Okay, let's add them up...
\[\Large \frac12x + \frac4{x+12}\]

Answer 13

wait 1/2x x is also on the denominator

Answer 14

You could have said that earlier :/
\[\Large \frac1{2x}+ \frac4{x+12}\]
better now? :P

Answer 15

yup, xD sorry didn't noticed that

Answer 16

Okay, you know how to add fractions?
Because it'd be much prettier if it had only one fraction bar, aight?

Answer 17

yup,

Answer 18

So can you add fractions?

Answer 19

yup,

Answer 20

Well then, add them :P

Answer 21

but not with variables, xD

Answer 22

can please just do the solution and explain it to me,, i still have to study chem ap and biotech, we have exams, T_T

Answer 23

Fine, I'll do the addition, you do the subtraction (it's basically the same, anyway)
Sound fair? :P

Answer 24

agree

Answer 25

The trick to adding or subtracting (dissimilar, or unlike denominators) fractions such as
\[\Large {\frac1{2x}}+ {\frac4{x+12}}= \color{red}{\frac{\color{white}{xxxxxx}}{}}\]

The denominator of the sum (difference) is simply the product of the denominators...
\[\Large {\frac1{2x}}+ {\frac4{x+12}}= \color{red}{\frac{\color{white}{xxxxxx}}{2x(x+12)}}\]

Catch me so far?

Answer 26

yup.

Answer 27

\[\Large {\frac1{\color{green}{2x}}}+ {\frac4{\color{blue}{x+12}}}= \color{red}{\frac{\color{white}{xxxxxx}}{\color{green}{2x}\color{blue}{(x+12)}}}\]

Answer 28

In the numerator, you 'cross' it. What I mean is that the left numerator is multiplied to the right denominator...
\[\Large {\frac1{\color{green}{2x}}}+ {\frac4{\color{blue}{x+12}}}= \color{red}{\frac{1\color{blue}{(x+12)}}{\color{green}{2x}\color{blue}{(x+12)}}}\]

And the right numerator is multiplied to the left denominator
\[\Large {\frac1{\color{green}{2x}}}+ {\frac4{\color{blue}{x+12}}}= \color{red}{\frac{1\color{blue}{(x+12)}+4(\color{green}{2x})}{\color{green}{2x}\color{blue}{(x+12)}}}\]

Answer 29

Can you simplify this?

Answer 30

\[\frac{ x+12 +8x}{2x ^{2}+24x }\]

Answer 31

Well now, that's really good :P
Except you forgot to combine these.
\[\huge \frac{ \color{red}x+12 +\color{red}{8x}}{2x ^{2}+24x }\]
YOU FAIL!!!!!

haha just kidding
Though seriously, combine those, and that's your answer :P

Answer 32

\[\frac{ 9x+12 }{ 2x ^{2} }\]

Answer 33

+24x

Answer 34

Much better...


Okay, general rule... regardless...
\[\Large \frac{a}b \pm \frac{c}d = \frac{ad \pm bc}{bd}\]

Answer 35

okay..i'm gonna study other subjects now, thanks by the way,,

Answer 36

You haven't done product or quotient yet, though.
Stay awhile, this'll take less than five minutes...

Answer 37

i really need to go, i know how to answer the product and quo just needed the sum and difference.xD

Answer 38

Please hold your peace, I meant no offense. I also didn't expect that much hostility from you.

I'm in a good mood, I usually am, but if you really think the one you are having a comment war with on youtube is an idiot, it'd be best if you just let them be. This is the internet, if you expect every single one of the three hundred fifty million users to be friendly with you, you're gonna have a bad time.

Answer 39

It looks like somebody has been working on the 'making comedy videos' thing...

Nice to see that you appear to be doing fine :)

Answer 40

someone's stalking me

Answer 41

.xD hahaha

Answer 42

ehh...
Until we meet again... Derek... <insert evil laugh>

Name's Teejay, for future reference

I'll be sure not to underestimate you again...

Answer 43

okaay, xD bye, thanks for the time though,