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Chemistry 7 Online
OpenStudy (anonymous):

In the important industrial process for producing ammonia (the Haber Process), the overall reaction is: N2(g) + 3H2(g) → 2NH3(g) + 100.4 kJ A yield of NH3 of approximately 98% can be obtained at 200°C and 1,000 atmospheres of pressure. How many grams of N2 must react to form 1.7 grams of ammonia, NH3? 0.51 g 1.0 g 1.4 g 2.8 g

OpenStudy (anonymous):

i think it's 1.0 g but i'm not sure..

OpenStudy (chmvijay):

can you tell molar mass of N2 and NH3

OpenStudy (anonymous):

28 17 idk hahaha

OpenStudy (anonymous):

because N is 14 and H is 1 if im correct.

OpenStudy (chmvijay):

yaaa ur right

OpenStudy (anonymous):

so 1.0 is correct.? or am i doing this wrong..

OpenStudy (chmvijay):

now from equation i can write 17*2 gram of ammonia is synthesized by 28 g of N2 then 1.7 gram of ammonia is synthesized by =28*1.7/34

OpenStudy (anonymous):

ahh, 1.4. got it

OpenStudy (chmvijay):

great :)

OpenStudy (anonymous):

thanks.(:

OpenStudy (chmvijay):

yw

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