find the surface area of the cylinder with radius 4 and height 10
Think of it as a net, with the rectangular " middle part" and the two cross-sections, the sum of the surface areas of these three = total surface area of the cylinder
the sum of the surface areas of the cross-sections are 2(pi x radius x radius) = 2(3.14 x 4 x)
2( 3.14 x 4 x 4) *
these are the answer a) 276.32 units² b) 351.68 units² c) 502.4 units² d) 3140 units
We know that the height of the rectangle is 10. The base is equal to the circumference of the circular cross-sections, eg. 3.14 x 8, ( being the diameter), so the area of the rectangular section is 10(3.14 x 8), or 3.14x 80. Add the results together; 2(3.14 x 4 x 4) + (3.14 x 80) = total surface area
b is the answer.
Yes
thanks
can you help me with this one please Find the surface area of a cone with radius 5 and slant height 8.
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