Question

log2^n=1/4log2^16+1/2log2^49?

Answer 1

You can drop the n since it is a logarith and then solve:\[\log(2^{n})=nlog2 \rightarrow n=\frac{ \frac{ 1 }{ 4 }\log(2^{16})+\frac{ 1 }{ 2 }\log (2^{49}) }{ \log2 }=\frac{ 4+\frac{ 49 }{ 2 } }{ 1 }=\]

Answer 2

Thanx!