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Integrate this thing ! inside
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\[\int\limits_{}^{} \frac{dx} {(1+\sqrt{x})\sqrt{x-x^2}}\]
denominator = (1-x) sqrtx , right ?
no
oh yes its not, sorry :P
you can do this sqrt(x-x^2) = sqrtx . sqrt(1-x) and 1/(1+sqrtx) = (1-sqrtx)/(1-x) see if this helps
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I think this wud help... Den.= (1+sqrtx)sqrtx sqrt(1-x) If we do the substitution 1+sqrtx = t , I think the den. wud be simplified...
sqrt(1-x) wont get simplified by that substitution ! @saloniiigupta95
If I am not wrong, it would go on to be, sqrt(1-x) = sqrt{1- (1-t)^2} = sqrt(2t-t^2) After all this, it changes to, |dw:1371660578719:dw| ... See if this helps...
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