How to calculate ∜(i+1) ?

Question

ivancsc1996 · Answer

I don't think you can do it with algebra. I guess a calculator.

amistre64 · Answer

$$(1+i)^{1/4}$$
might help to do some arg and mod$$mod~(\cos(arg)+i~\sin(arg))$$
given a+bi

mod=sqrt{a^2+b^2}
arg = inverse tan(b/a)

amistre64 · Answer

then its just a matter of

mod^(1/4), times [ cos(4arg) + i sin(4 arg)]

if memory serves

ivancsc1996 · Answer

Wow, what was that.

anonymous · Answer

Well, that's something too complicated! There should be an easier way, because it's an exam task.

amistre64 · Answer

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amistre64 · Answer

there are different ways to approach it ...

mathslover · Answer

Using polar form may be easy here?

mathslover · Answer

$\sqrt{1+i} ~\textbf{in polar form is : } ~ \sqrt{2} e^{\cfrac{i\pi}{4}} $

mathslover · Answer

Related discussion here : http://openstudy.com/study#/updates/4e353f760b8ba7b2da426553 The above post has some mistake, it is "1+i" and not "$\sqrt{1+i} $ "