Question

How to calculate ∜(i+1) ?

Answer 1

I don't think you can do it with algebra. I guess a calculator.

Answer 2

\[(1+i)^{1/4}\]
might help to do some arg and mod\[mod~(\cos(arg)+i~\sin(arg))\]
given a+bi

mod=sqrt{a^2+b^2}
arg = inverse tan(b/a)

Answer 3

then its just a matter of

mod^(1/4), times [ cos(4arg) + i sin(4 arg)]

if memory serves

Answer 4

Wow, what was that.

Answer 5

Well, that's something too complicated! There should be an easier way, because it's an exam task.

Answer 6

there are different ways to approach it ...

Answer 7

Using polar form may be easy here?

Answer 8

\(\sqrt{1+i} ~\textbf{in polar form is : } ~ \sqrt{2} e^{\cfrac{i\pi}{4}} \)

Answer 9

Related discussion here : http://openstudy.com/study#/updates/4e353f760b8ba7b2da426553

The above post has some mistake, it is "1+i" and not "\(\sqrt{1+i} \) "