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Which equation would you use to find the statistical definition of entropy?
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i think \[dS=\frac{ dQ }{ dT }\]
Guys help me in this one! It takes Andy 0.50 seconds to lift a 98-newton box from the floor and place it on the table. If he expends a constant power of 137 watts during this time, what is the height of the table?
Ok, so power is the rate at which work is done. Work is the change in energy of the object. In this case the work done is the energy given to the box as potnetial energy. You just need to solve for h in this equation:\[P=W/t=\Delta E/t=mgh/t \rightarrow h=\frac{ Pt }{ mg }=\frac{ 137W 0.5s}{ 98N }\approx 0.7m\]
@anna.s214
The answer is 0.69m
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ahh thank you, you were right!
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