Question

Jose's math final is worth 100 points and consists of 45 test questions. Multiple choice questions are worth 2 points and application questions are worth 4 points. How many application problems are on the test?
A. 3
B. 5
C. 7
D. 9

Answer 1

m + a = 45 and 2m + 4a = 100

You now just simply solve those 2 simultaneous equations. Can you do that or would you like further help?

Answer 2

If you are going to attempt solving those and don't know where to start, I would suggest the elimination method. Multiply both sides of the first equation by -2 and add that new equation to the second equation. Add left side to left side and right to right.

Answer 3

The "m" variable will drop out and you will be left with one equation in one variable which is:

"a"

Answer 4

All good now, @Reganbaughman417 ?

Answer 5

Yes thank you @tcarroll010

Answer 6

uw!

Answer 7

Good luck to you in all of your studies and thx for the recognition! @Reganbaughman417

Answer 8

Thank you and your welcome! (:

Answer 9

First let's put this in equation form. Let M stand for Multiple choice and A stand for application questions. So there are 45 questions on this test so this is the equation we have for this question.

M+A=45

And We also know that the Multiple choice questions are worth 2 points and the Application 4 points and that the test is worth 100 points. So that gives us the equations:

2(M) + 4(A)=100

Now we go back to the first equations and let's subtract the application questions from 45.

M+A=45
-A -A
M=45-A

Now we go to the second equation and substitute M in:

2(45-A) +4(A)=100

So now you distribute and solve

90-2A+4A=100
-90 -90

-2A+4A=10
2A=10

A=5

So 5 application questions