Question

HELPPPPP!!!

Answer 1

http://prntscr.com/1at53h

Answer 2

WHAT U THINK ?

Answer 3

i guess parabola , but its just a guess!

Answer 4

circle doesn't have 2xy
parabola either have x^2 or y^2 but not both...

Answer 5

pair of lines through origin
(y-mx)(y-mx) =0
you will get this in the required form....

Answer 6

circle :x^2+y^2=r^2

Answer 7

pair of lines through origin : ax^2+2hxy+y^2=0
http://www.cuemath.com/2012/sl016-straight-lines-introduction-to-pair-of-straight-lines/

Answer 8

doubts?

Answer 9

so you mean any straight line if when we multiply them both will give 0?

Answer 10

no no...
equation of "pair" of lines, we get by multiplying individual equations ...
L1 : y=mx ----> y-mx=0
L2: y=mx ----->y-mx=0
pair L1L2 : (y-mx)(y-mx)=0
now this is in the form of ax^2+2hxy+by^2=0

Answer 11

see the link also for better understanding...

Answer 12

i am confused

Answer 13

and from where the 'h' comes from?

Answer 14

its just that form...one term with x^2, one term with y^2 and one term with xy
(y-mx)(y-mx)=0 <----multiply and see by yourself......

Answer 15

it gives y2-2mxy+mx2
it is giving a negative 2mxy whereas in the eq it is positive!

Answer 16

that equation is general equation...like in ax^2+bx+c= 0, b can be anything,0,-4,6,...

Answer 17

ok so it is a eq just for a pair of lines passing through the origin right?

Answer 18

yes!

Answer 19

one more question
this eq is cannot be used for pair of lines that does not pass through origin right?

Answer 20

@hartnn

Answer 21

yeah, it cannot
(ax+by+c)(ax+by+c) =0
has the form
ax^2+2hxy+by^2+2gx+2fy+k=0

Answer 22

oh god! this is too much too engulf!
anyways thanks for the help :D
i got it now :)

Answer 23

welcome ^_^