Question

Solve the triangle:
A = 51°, b = 14, c = 6

Answer 1

@Loser66

Answer 2

@e.mccormick i just need a, B, and C

Answer 3

or else?

Answer 4

law of cosines gives us \[a^2=b^2+c^2-2bc~cosA\]
the rest is elementary

Answer 5

Yeah thats it, I just need a C and B

Answer 6

232 - 2(14)(6)cos51 = a^2
How do i do it?

Answer 7

solving for the angle part:

\[C=cos^{-1}\left(\frac{c^2-a^2-b^2}{-2ab}\right)\]
\[B=cos^{-1}\left(\frac{b^2-a^2-c^2}{-2ac}\right)\]

Answer 8

you generally do it with a calculator

Answer 9

but how do i do this? 232 - 2(14)(6)cos51 = a^2

Answer 10

http://www.wolframalpha.com/input/?i=sqrt%2814%5E2%2B6%5E2-2%286%29%2814%29*cos%2851%29%29

Answer 11

Thanks! Just that one value gave me the other ones.

Answer 12

:)