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Mathematics 21 Online
OpenStudy (anonymous):

Help with this!

OpenStudy (anonymous):

with what??

OpenStudy (anonymous):

OpenStudy (anonymous):

oh i see

OpenStudy (anonymous):

sooo??

OpenStudy (anonymous):

@hartnn

OpenStudy (anonymous):

dependent events are not necessarily mutually exclusive

OpenStudy (anonymous):

if iam not wrong , mutually exclusive events are independent right?

OpenStudy (anonymous):

so forget about II it is wrong no no, mutually exclusive and independent are two separate conceps in fact, if you know the events are mutually exclusive they are DEPENDENT because if you know one occurs you know the other does not occur

OpenStudy (anonymous):

so III is correct, mutually exclusive events are dependent

OpenStudy (anonymous):

i am confused!

OpenStudy (anonymous):

ok lets give a simple example

OpenStudy (anonymous):

sure!

OpenStudy (anonymous):

it is not possible for you to roll a die and get both a total of 7 and a total of 8 right?

OpenStudy (anonymous):

those events are MUTUALLY EXCLUSIVE because their intersection is empty

OpenStudy (anonymous):

i mean roll dice, not a single die that was my mistake but it is not possible to roll two dice and get 7 and 8 at the same time, you can get a 7 or you can get an 8 but you cannot get both

OpenStudy (anonymous):

now if i say A is the event you roll a 7, and B is the event you roll an 8, then \[P(A|B)=0\] because if you know you rolled an 8 you know you did not roll a 7

OpenStudy (anonymous):

why? if i roll two dice i can get 7 on one and 8 on the other?

OpenStudy (anonymous):

since \(P(A|B)=0\) but \(P(A)=\frac{1}{6}\) we know these events are DEPENDENT

OpenStudy (anonymous):

oh no sorry i got it

OpenStudy (anonymous):

you meant a total of 7 and total of 8 right?

OpenStudy (anonymous):

and what does this mean P(A|B)?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

where were you gone???

OpenStudy (anonymous):

this means that \[P(A|B)=0\] because if you know you have rolled an 8, you know you cannot have rolled a 7

OpenStudy (anonymous):

and therefore A and B are DEPENDENT

OpenStudy (anonymous):

so III is correct

OpenStudy (anonymous):

now how about I ?

OpenStudy (anonymous):

the line between alpha bet A nd B indicates what in this P(A|B)?

OpenStudy (anonymous):

refresh your browser you should be able to see P(A|B)

OpenStudy (anonymous):

as for I, if A and B are independent, that means \[P(A\cap B)=P(A)\times P(B)\]

OpenStudy (anonymous):

either way it is a line just like it is in question!

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

if \(P(A)>0\) and \(P(B)>0\) then \[P(A)P(B)>0\]

OpenStudy (anonymous):

so A and B cannot be mutually exclusive

OpenStudy (anonymous):

so the answer is C?

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