Help with this!
with what??
oh i see
sooo??
@hartnn
dependent events are not necessarily mutually exclusive
if iam not wrong , mutually exclusive events are independent right?
so forget about II it is wrong no no, mutually exclusive and independent are two separate conceps in fact, if you know the events are mutually exclusive they are DEPENDENT because if you know one occurs you know the other does not occur
so III is correct, mutually exclusive events are dependent
i am confused!
ok lets give a simple example
sure!
it is not possible for you to roll a die and get both a total of 7 and a total of 8 right?
those events are MUTUALLY EXCLUSIVE because their intersection is empty
i mean roll dice, not a single die that was my mistake but it is not possible to roll two dice and get 7 and 8 at the same time, you can get a 7 or you can get an 8 but you cannot get both
now if i say A is the event you roll a 7, and B is the event you roll an 8, then \[P(A|B)=0\] because if you know you rolled an 8 you know you did not roll a 7
why? if i roll two dice i can get 7 on one and 8 on the other?
since \(P(A|B)=0\) but \(P(A)=\frac{1}{6}\) we know these events are DEPENDENT
oh no sorry i got it
you meant a total of 7 and total of 8 right?
and what does this mean P(A|B)?
right
where were you gone???
this means that \[P(A|B)=0\] because if you know you have rolled an 8, you know you cannot have rolled a 7
and therefore A and B are DEPENDENT
so III is correct
now how about I ?
the line between alpha bet A nd B indicates what in this P(A|B)?
refresh your browser you should be able to see P(A|B)
as for I, if A and B are independent, that means \[P(A\cap B)=P(A)\times P(B)\]
either way it is a line just like it is in question!
yes
if \(P(A)>0\) and \(P(B)>0\) then \[P(A)P(B)>0\]
so A and B cannot be mutually exclusive
so the answer is C?
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