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Mathematics 6 Online
OpenStudy (anonymous):

help! http://prntscr.com/1at5k0

OpenStudy (anonymous):

do u know how to find the inver4se function?

OpenStudy (anonymous):

the range of a function is the domain of the inverse

OpenStudy (anonymous):

i knew it but i cannot remember it clearly now can you tell

OpenStudy (anonymous):

@julian25

OpenStudy (jdoe0001):

what's the range of a function?

OpenStudy (anonymous):

the y values

OpenStudy (jdoe0001):

right, so let's plug a few values in "x", and let's see what "y" becomes

OpenStudy (anonymous):

ok..

OpenStudy (jdoe0001):

let's say x = 10, 1,000, 1,000,000 so y becomes \(\cfrac{1}{9},\cfrac{1}{999},\cfrac{1}{999,999}\)

OpenStudy (anonymous):

yeah

OpenStudy (jdoe0001):

1/999,999 is really LESS than 1

OpenStudy (anonymous):

ahan...

OpenStudy (jdoe0001):

let's say x = -10, -1,000, -1,000,000 y becomes \(-\cfrac{1}{11},-\cfrac{1}{1,001},-\cfrac{1}{1,000,001} \)

OpenStudy (jdoe0001):

so, - 1/1,000,001 is really LESS than -1

OpenStudy (jdoe0001):

both of those values are a fraction, not 0, so, they're NOT 0, but LESS than -1 or 1

OpenStudy (jdoe0001):

and notice that the "numerator" never changed

OpenStudy (jdoe0001):

so, what do you think is the range from the choices given?

OpenStudy (anonymous):

@jdoe0001 A ?

OpenStudy (jdoe0001):

well, it says all real numbers, but 0 or \(\pm \infty\)

OpenStudy (jdoe0001):

well, -10 is NOT 0, but is a real number, and "y" never became -10, or 10 or even 2 or -2

OpenStudy (anonymous):

i am not getting anything :(

OpenStudy (jdoe0001):

well, let's read B) it says the set of all rational number BUT 0 let's read C) all rational fractions \(\large \frac{p}{q}\) where is always p=1, and q is never 0 let's read D) all possible rational numbers so, which one do you think?

OpenStudy (anonymous):

@jdoe0001 i think C

OpenStudy (jdoe0001):

hmmmm, what makes "C" so attractive?

OpenStudy (jdoe0001):

let's read it again

OpenStudy (anonymous):

ok

OpenStudy (jdoe0001):

\(\large \frac{p}{q}\) where "p" is always 1, so really \(\large \frac{1}{q}\) and "q" is never 0 well, originally it said that "x" was the "set of all integers BUT 1" if "x" becomes 1, "q" turns to 0 that is "x-1" x= 0 "1-1 = 0"

OpenStudy (jdoe0001):

so, with THAT RESTRICTION that "x" is "the set of all integers BUT 1" pretty much guarantees that "q" in \(\frac{p}{q} \) NEVER becomes 0

OpenStudy (anonymous):

yes

OpenStudy (jdoe0001):

so, that's your range, a bunch of fractions, which are NEVER -1 OR 1 ever closing in to 0 but never getting to 0 :)

OpenStudy (anonymous):

so the answer is C?

OpenStudy (jdoe0001):

from the restrictions and notation, yes

OpenStudy (anonymous):

ah finally! thanks a ton :)

OpenStudy (jdoe0001):

yw

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