Use a table to find a z-score that fits the given conditions. Interpolate if necessary. 10% of the area under the standard normal curve is above the score. Can anyone explain how to do this? I'm lost.
sounds like you want to find the value of k such that P(Z > k) = 0.10
are you allowed to use a calculator?
yes
yes, I am.
ok one calculator you can use is wolfram alpha you would use the normalcdf function to get this http://www.wolframalpha.com/input/?i=normalcdf&a=*C.normalcdf-_*Formula.dflt-&f2=0.10&x=0&y=0&f=NormalProbabilities.pr_0.10&a=*FVarOpt.1-_***NormalProbabilities.pr--.***NormalProbabilities.z--.**NormalProbabilities.l-.*NormalProbabilities.r---.*--&a=*FVarOpt.2-_**-.***NormalProbabilities.mu--.**NormalProbabilities.sigma---.**NormalProbabilities.pr--- notice how there is a line on that page that says P(Z > 1.282) = 0.1 so k = 1.282 is the value we're looking for
Okay that makes sense. I am still a little confused how you figured out how 0.1 = 1.282
they aren't equal like that
its more like P(Z > 1.282) = 0.10
in other words the probability of picking a z-score larger than 1.282 is 0.10 (or 10%)
okay so lets say another question asks 33% of the area under the standard normal curve is above the score. Then would the answer be -.44 ?
on that calculator page, you now type in 0.33
then you look for the line that has P(Z > ???) = 0.33
okay so it is 0.44 not negative
yep P(Z > 0.44) = 0.33
Thank you for your help ! :)
you're welcome
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